golang 中 strings 包的 Replace 用法介绍

函数声明为:

func Replace(s, old, new string, n int) string
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官方描述为:

返回将s中前n个不重叠old子串都替换为new的新字符串,如果n<0会替换所有old子串。
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示例代码为,每行的结果见每行上面的注释部分:

func main() {
// non-overlapping: “123” repeat 6 times in s
s := “123lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l”
old := “123”
new := “888”

fmt.Println(“non-overlapping: “)
// n < 0 ,用 new 替换所有匹配上的 old;n=-1: 888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla888l
fmt.Println(“n=-1: “, strings.Replace(s, old, new, -1 ))

// 不替换任何匹配的 old;n=0: 123lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l
fmt.Println(“n=0: “, strings.Replace(s, old, new, 0 ))

// 用 new 替换第一个匹配的 old;n=1: 888lafaldsjglad123lkfasdf123djfal123lkdjga123lksjfla123l
fmt.Println(“n=1: “, strings.Replace(s, old, new, 1 ))

// 用 new 替换前 5 个匹配的 old(实际多于 5 个);n=5: 888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla123l
fmt.Println(“n=5: “, strings.Replace(s, old, new, 5 ))

// 用 new 替换前 7 个匹配上的 old(实际没那么多);n=7: 888lafaldsjglad888lkfasdf888djfal888lkdjga888lksjfla888l
fmt.Println(“n=7: “, strings.Replace(s, old, new, 7 ))

// overlapping:
s = “888888888888888888”
old = “888”
new = “666”
fmt.Println(“overlapping: “)

// n < 0 ,用 new 替换所有匹配上的 old;n=-1: 666666666666666666
fmt.Println(“n=-1: “, strings.Replace(s, old, new, -1 ))

// 不替换任何匹配的 old;n=0: 888888888888888888
fmt.Println(“n=0: “, strings.Replace(s, old, new, 0 ))

// 用 new 替换第一个匹配的 old;n=1: 666888888888888888
fmt.Println(“n=1: “, strings.Replace(s, old, new, 1 ))

// 用 new 替换前 5 个匹配的 old(实际多于 5 个);n=5: 666666666666666888
fmt.Println(“n=5: “, strings.Replace(s, old, new, 5 ))

// 用 new 替换前 7 个匹配上的 old(实际没那么多);n=7: 666666666666666666
fmt.Println(“n=7: “, strings.Replace(s, old, new, 7 ))
}

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